# eV to kg Conversion

For eV to kg conversion, use $E=mc^{2}$ to convert Joules to kg and then use the fact that 1 eV is the energy required to move a charge $e$ across a potential difference of 1 volt. Thus 1 eV is $1.6 \times 10^{-19} \times 1$ Joules. Therefore
$m ({\rm kg}) = \frac{e E({\rm eV})}{c^{2}}$
$m ({\rm kg}) = 1.780 \times 10^{-36} \ E({\rm eV})$