# kg to eV Conversion

Access list of astrophysics formulas download page:

For kg to eV conversion, use $E=mc^{2}$ to convert 1 kg to Joules and then use the fact that 1 eV is the energy required to move a charge $e$ across a potential difference of 1 volt. Thus 1 eV is $1.6 \times 10^{-19} \times 1$ Joules. Therefore

\[

E({\rm eV}) = \frac{m ({\rm kg}) \ c^{2}}{e}

\]

or

\[

E({\rm eV}) = 5.6175 \times 10^{35} \ m ({\rm kg})

\]