# MeV to kg Conversion

For MeV to kg Conversion, yse $E=mc^{2}$ to convert Joules to kg and then use the fact that 1 MeV is the energy required to move a charge $e$ across a potential difference of $10^{6}$ volts. Thus 1 MeV is $1.6 \times 10^{-19} \times 10^{6}$ Joules. Therefore
$m ({\rm kg}) = \frac{10^{6} \ e E({\rm MeV})}{c^{2}}$
$m ({\rm kg}) = 1.780 \times 10^{-30} \ E({\rm MeV})$