# Temperature in keV to Kelvin Conversion

$T \ ({\rm Kelvin}) \sim 1.16 \times 10^{7} T \ ({\rm keV}) .$
as such, the Boltzmann constant is implied ($kT$ has units of energy).
By definition, 1 eV is the energy required to move a charge of $e$ through a potential difference of 1 volt so is equal to $1.6 \times 10^{-19} \times 1$ Joules.
With $k=1.38 \times 10^{-23} \ \rm J \ K^{-1}$, multiply keV by 1000 to get eV, multiply by $e$ to get Joules, divide by $k$ to get $T$ in Kelvin:
$\frac{1000 e}{k} = \frac{10^{-3} \times 1.6 \times 10^{-19}}{1.38 \times 10^{-23}} = 1.159 \times 10^{7}$